Initial capacitor has plate separation 5 mm with capacitance C1=ϵ0A/5.
After inserting 2 mm mica sheet, the gap remaining is 3 mm of air. The effective separation becomes: deff=3+2/k where k is the dielectric constant of mica.
New capacitance: C2=3+2/kϵ0A
Since battery remains connected, voltage is constant. The charge is: Q=CV
Ratio of charges: Q1Q2=C1C2=ϵ0A/5ϵ0A/(3+2/k)=3+2/k5
Given that charge increases by 25%: Q2=1.25Q1
3+2/k5=1.25
5=1.25(3+2/k)
5=3.75+2.5/k
1.25=2.5/k
k=2