U=−PEcosθwext=ΔU=Uf−Ui=−PEcos180∘+PEcos0∘wext=2PE=2×(4×10−6)(18)×104=144×10−2=14.4 mJ
Two point charges -4 μ c and 4 μ c, constituting an electric dipole, are placed at (-9,0,0) cm and (9,0,0) cm in a uniform electric field of strength…
JEE Main 2025 — Physics Electromagnetism
Two point charges −4μc and 4μc, constituting an electric dipole, are placed at (−9,0,0)cm and (9,0,0)cm in a uniform electric field of strength 104NC−1. The work done on the dipole in rotating it from the equilibrium through 180∘ is :
Held on 23 Jan 2025 · Verified 6 Jul 2026.
Options
- A
18.4 mJ
- B
14.4 mJ
- C
12.4 mJ
- D
16.4 mJ
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