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Two cells of emf 1 V and 2 V and internal resistance 2 Ω and 1 Ω, respectively, are connected in series with an external resistance of 6 Ω. The total…

JEE Main 2025 — Physics Electromagnetism

2025integermedium

Two cells of emf 1 V and 2 V and internal resistance 2Ω2 \Omega2Ω and 1Ω1 \Omega1Ω, respectively, are connected in series with an external resistance of 6Ω6 \Omega6Ω. The total current in the circuit is I1\mathrm{I}_1I1​. Now the same two cells in parallel configuration are connected to same external resistance. In this case, the total current drawn is I2I_2I2​. The value of (I1I2)\left(\frac{I_1}{I_2}\right)(I2​I1​​) is x3\frac{x}{3}3x​. The value of xxx is _____.

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Held on 3 Apr 2025 · Verified 6 Jul 2026.

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