After dielectric
$\begin{aligned}
& \mathrm{C}_1=4 \mathrm{C} \
& \mathrm{C}_1=4 \times 5=20 \mu \mathrm{F} \
& \mathrm{C}_2=\mathrm{C}_3=5 \mu \mathrm{F}
\end{aligned}$
C1&C2 are in series which is parallel to C3 So
$\begin{aligned}
& C_{c q}=\frac{C_1 C_2}{C_1+C_2}+C_3 \Rightarrow \frac{20 \times 5}{20+5}+5 \
& =4+5=9 \mu \mathrm{~F}
\end{aligned}$
Correct Option (3)
