
IA=ω2πNqIA=2πNqω,IB=0IA=IB=2πNqω
JEE Main 2025 — Physics Electromagnetism

N equally spaced charges each of value q , are placed on a circle of radius R . The circle rotates about its axis with an angular velocity ω as shown in the figure. A bigger Amperian loop B encloses the whole circle where as a smaller Amperian loop A encloses a small segment. The difference between enclosed currents, IA−IB, for the given Amperian loops is
Held on 24 Jan 2025 · Verified 6 Jul 2026.
N2πqω
2πN2qω
πNqω
2πNqω
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