The magnetic force on a moving charge is given by the Lorentz force law: $\vec{F} = q(\vec{v} \times \vec{B})$. The magnitude is $F = qvB\sin\theta$, where $\theta$ is the angle between $\vec{v}$ and $\vec{B}$.
Back to JEE Main 2025 Electromagnetism
JEE Main 2025 — Physics Electromagnetism
medium
mcq
2025
Official previous-year question
Verified 30 May 2026.
Question
The magnitude of force on a charge $q$ moving with velocity $v$ in a magnetic field $B$ at angle $\theta$ is:
Options
- A
$F = qvB\sin\theta$
- B
$F = qvB\cos\theta$
- C
$F = qvB$
- D
$F = \frac{qB}{v}$
Solution
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