Maximum possible magnetic field is at the surface $\begin{aligned}
& \mathrm{B}{\max }=\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{a}} \
& \frac{\mathrm{~B}{\max }}{2}=\frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{a}}
\end{aligned}ItcanbeobtainedinsideaswellasoutsidethewireForinside,\begin{aligned}
& \frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{a}}=\frac{\mu_0 \mathrm{Ir}}{2 \pi \mathrm{a}^2} \
& \Rightarrow \mathrm{r}=\frac{\mathrm{a}}{2}
\end{aligned}Foroutside\begin{aligned}
& \frac{\mu_0 \mathrm{I}}{4 \pi \mathrm{a}}=\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}} \
& \Rightarrow \mathrm{r}=2 \mathrm{a}
\end{aligned}Correctanswer\left[\frac{\mathrm{a}}{2}, 2 \mathrm{a}\right]$