Skip to main content

An ac current is represented as i=5 √2+10 cos (650 π t+ π 6 ) Amp The r.m.s value of the current is

JEE Main 2025 — Physics Electromagnetism

2025mcqeasy

An ac current is represented as

i=52+10cos⁡(650πt+π6)Amp\mathrm{i}=5 \sqrt{2}+10 \cos \left(650 \pi \mathrm{t}+\frac{\pi}{6}\right) \mathrm{Amp}i=52​+10cos(650πt+6π​)Amp

The r.m.s value of the current is

Official previous-year question

Held on 7 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    50 Amp

  2. B

    100 Amp

  3. C

    10 Amp

  4. D

    52Amp5 \sqrt{2} \mathrm{Amp}52​Amp

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Electromagnetism in other years

More JEE Main Electromagnetism questions

Other Physics topics for JEE Main

Keep practicing Electromagnetism

Work through every JEE Main Electromagnetism PYQ, year by year.

Browse all Physics topics