Since time period of a revolving charge is qB2πm Where B= magnetic field due to a solenoid =μ0nI $\begin{aligned}
& \therefore \mathrm{T}=\frac{2 \pi \mathrm{m}}{\mathrm{q}\left(\mu_0 \mathrm{nI}\right)} \
& 75 \times 10^{-9}=\frac{(2 \pi)\left(9 \times 10^{-31}\right)}{1.6 \times 10^{-19} \times 4 \pi \times 10^{-7} \times \mathrm{n} \times 1.5} \
& \mathrm{N}=250
\end{aligned}$