$\begin{aligned}
& Q=c V \
& V=\frac{Q}{c}=\frac{i t}{\left(\frac{\varepsilon_0 A}{d}\right)} \
& d=\frac{\varepsilon_0 \pi r^2}{i}\left(\frac{v}{t}\right)
\end{aligned}Puttingvalues\begin{aligned}
d & =\frac{9 \times 10^{-12} \times \frac{22}{7} \times(0.1)^2}{0.15} \times\left(7 \times 10^8\right) \
& =1320 \mu \mathrm{~m}
\end{aligned}$
A parallel plate capacitor consisting of two circular plates of radius 10 cm is being charged by a constant current of 0.15 A . If the rate of change…
JEE Main 2025 — Physics Electromagnetism
A parallel plate capacitor consisting of two circular plates of radius 10 cm is being charged by a constant current of 0.15 A . If the rate of change of potential difference between the plates is 7×108 V/s then the integer value of the distance between the parallel plates is ( Take, ϵ0=9×10−12 m F,π=722) ________ μm.
Held on 29 Jan 2025 · Verified 6 Jul 2026.
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