
Let B be the magnetic field due to single side $\begin{aligned}
& \text { then } B=\frac{\mu_0 \mathrm{i}}{4 \pi \mathrm{~d}}\left(\sin \theta_1+\sin \theta_2\right) \
& =\frac{10^{-7} \times 5 \times 2}{\frac{1}{2 \sqrt{2}}} \times \frac{1}{\sqrt{2}}=2 \times 10^{-6} \
& \therefore B_{\text {net }} \text { at centre } O=4 B \
& =8 \times 10^{-6}
\end{aligned}$