Energy gained due to potential difference by charged particle:
KE=qV
Relation between momentum & kinetic energy:
p=2m(KE)
Now, radius of the circular path under magnetic field will be given by,
R=qBmv=qBp=qB2m(KE)=qB2mqV
Therefore,
R∝m⇒m∝R2
⇒m2m1=(R2R1)2