Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region…
JEE Main 2024 — Physics Electromagnetism
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Two particles X and Y having equal charges are being accelerated through the same potential difference. Thereafter, they enter normally in a region of uniform magnetic field and describes circular paths of radii R1 and R2 respectively. The mass ratio of X and Y is :
Official previous-year question
Held on 29 Jan 2024 · Verified 6 Jul 2026.
Options
A
(R1R2)2
B
(R2R1)2
C
(R2R1)
D
(R1R2)
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Solution
Energy gained due to potential difference by charged particle:
KE=qV
Relation between momentum & kinetic energy:
p=2m(KE)
Now, radius of the circular path under magnetic field will be given by,
R=qBmv=qBp=qB2m(KE)=qB2mqV
Therefore,
R∝m⇒m∝R2
⇒m2m1=(R2R1)2
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