The common potential after connection would be, VC=Cnetqnet=2CCV+C(2V)
⇒VC=23V
Therefore, loss of energy
=21CV2+21C(2V)2−212C(23V)2
=(4CV2)
Two identical capacitors have same capacitance C. One of them is charged to the potential V and other to the potential 2V. The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is :
Held on 1 Feb 2024 · Verified 6 Jul 2026.
41CV2
2CV2
21CV2
43CV2
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