
Given the electric field is
E==0.20i^cmV20i^mV
The formula for calculating the torque is
τ=p×E...(1)
where,
p===ql4×[(2i^+(−1)j^+5k^)−(1i^+0j^+4k^)]4(i^−j^+k^)μCm
Thus, from equation (1), it follows that
τ=(4i^−4j^+4k^)×10−6×(20i^)Nm=(8k^+8j^)×10−5Nm⇒∣τ∣=82+82×10−5Nm=82×10−5Nm
Hence, α=2.