Power (P)=V.I $\begin{aligned}
& \Rightarrow 110=(220)(\mathrm{I}) \
& \Rightarrow \mathrm{I}=0.5 \mathrm{~A}
\end{aligned}$
Now, I=tn⋅e $\begin{aligned}
& \Rightarrow 0.5=\left(\frac{\mathrm{n}}{\mathrm{t}}\right)\left(1.6 \times 10^{-19}\right) \
& \Rightarrow \frac{\mathrm{n}}{\mathrm{t}}=\frac{0.5}{1.6 \times 10^{-19}} \
& \Rightarrow \frac{\mathrm{n}}{\mathrm{t}}=31.25 \times 10^{17}
\end{aligned}$