$\begin{aligned}& \mathrm{E}_0=\mathrm{B}_0 \mathrm{C} \& \mathrm{E}_0=3 \times 10^8 \times\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \& \mathrm{E}_0=105 \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}
\end{aligned}$ Data inconsistent while calculating speed of wave. You can challenge for data.
The magnetic field in a plane electromagnetic wave is B_ y= (3.5 × 10^-7 ) sin (1.5 × 10^3 x+0.5 × 10^11 t ) T. The corresponding electric field will…
JEE Main 2024 — Physics Electromagnetism
The magnetic field in a plane electromagnetic wave is By=(3.5×10−7)sin(1.5×103x+0.5×1011t)T. The corresponding electric field will be :
Held on 9 Apr 2024 · Verified 6 Jul 2026.
Options
- A
Ey=10.5sin(1.5×103x+0.5×1011t)Vm−1
- B
Ez=1.17sin(1.5×103x+0.5×1011t)Vm−1
- C
Ey=1.17sin(1.5×103x+0.5×1011t)Vm−1
- D
Ez=105sin(1.5×103x+0.5×1011t)Vm−1
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