Given E=E0cos(ωt−kz)i^:
Clearly, (ωt−kz) term represents, electromagnetic wave is travelling along +z direction or along k^.
Now, in vector form, direction of electromagnetive wave is given by C^=E^×B^. Therefore, magnetic field is along j^.
Also, we know that B0=CE0, where C is speed of light.
Therefore, B=CE0cos(ωt−kz)j^.