Given that
Current I=I0+βt, I0=20A and β=3As−1
The instantaneous current is given by
I=20+3t...(1)
Integrating equation (1), we have
dtdq=20+3t⇒∫0qdq=∫020(20+3t)dt⇒q=∫02020dt+∫0203tdt⇒q=[20t+23t2]020=1000C
JEE Main 2024 — Physics Electromagnetism
The electric current through a wire varies with time as I=I0+βt, where I0=20A and β=3As−1. The amount of electric charge crossed through a section of the wire in 20s is:
Held on 29 Jan 2024 · Verified 6 Jul 2026.
80C
1000C
800C
1600C
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