
2y−5+2y−0+1y−x+10=0y−5+y+2y−2x+20=04y−2x+15=0….( (i) 4x−5+4x−0+1x−10−y=0x−5+x+4x−40−4y=06x−4y−45=0..(i)4x−30=0−2x+4y+15=0..(ii)x=215&4y−15+15=0y=0i=1y−x+10i=10−7.5+10i=2.5A=10nAn=25
JEE Main 2024 — Physics Electromagnetism
The current flowing through the 1Ω resistor is 10n A. The value of n is _________ 
Held on 9 Apr 2024 · Verified 6 Jul 2026.
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A square loop of side $2$ cm is placed in a time varying magnetic field with magnitude as $B = 0.4\sin(300t)$ Tesla. The normal to the plane of loop makes an angle of $60°$ with the field. The maximum induced emf produced in the loop is __________ mV.
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