In an a.c. circuit, voltage and current are given by: V=100 sin(100t)V and I=100 sin(100t+ π 3) mA respectively. The average power dissipated in one…
JEE Main 2024 — Physics Electromagnetism
2024mcqmedium
In an a.c. circuit, voltage and current are given by: V=100sin(100t)V and I=100sin(100t+3π)mA respectively. The average power dissipated in one cycle is :
Official previous-year question
Held on 29 Jan 2024 · Verified 6 Jul 2026.
Options
A
5W
B
10W
C
2.5W
D
25W
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Solution
Standard expression of voltage is given by, V=V0sin(ωt) and for current is given by, I=I0sin(ωt+ϕ). Clearly, ϕ is the phase difference here. From the given expression, ϕ=3π.
Average power dissipated in one cycle is given by,
Pavg=VrmsIrmscos(ϕ)
=2100×2100×10−3×cos(3π)
=2104×10−3×21
=410=2.5W
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