(Emf)induced =−Ldtdi
In magnitude form, $\begin{aligned}
& \left|\operatorname{Emf}_{\text {ind }}\right|=\left|(-) L \frac{\mathrm{di}}{\mathrm{dt}}\right| \
& \Rightarrow 0.1=\frac{(\mathrm{L})[+2-(-2)]}{0.2} \
& \Rightarrow \mathrm{L}=\frac{0.1 \times 0.2}{4}=5 \mathrm{mH}
\end{aligned}$