
Electric field E at a distance r due to infinite long wire is E=r2kλ Force of electron ⇒F=eE $\begin{aligned}
& F=e\left(\frac{2 k \lambda}{r}\right) \
& F=\frac{2 k \lambda e}{r}
\end{aligned}$
This force will provide required centripetal force $\begin{aligned}
\mathrm{F} & =\frac{\mathrm{m}^2}{\mathrm{r}}=\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{r}} \
\mathrm{v} & =\sqrt{\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}} \
\mathrm{KE} & =\frac{1}{2} \mathrm{mv}^2=\frac{1}{2} \mathrm{~m}\left(\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}\right) \
& =\mathrm{k} \lambda \mathrm{e}
\end{aligned}$



