Force acting on a charged particle under the magnetic field is given by, F=q(v×B).
⇒5ek⏜=e(3i⏜+5j⏜)×(B0i⏜+2B0j⏜)
⇒5ek⏜=e(6B0k⏜−5B0k⏜)
⇒B0=5T
JEE Main 2024 — Physics Electromagnetism
An electron moves through a uniform magnetic field B=B0i^+2B0j^T. At a particular instant of time, the velocity of electron is u=3i^+5j^ms−1. If the magnetic force acting on electron is F=5ek^N, where e is the charge of electron, then the value of B0 is ____ T.
Held on 31 Jan 2024 · Verified 6 Jul 2026.
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