An electric charge 10^-6μ C is placed at origin (0,0) m of X-Y co-ordinate system. Two points P and Q are situated at (√3,√3)m and (√6,0)m…
JEE Main 2024 — Physics Electromagnetism
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An electric charge 10−6μC is placed at origin (0,0)m of X−Y co-ordinate system. Two points P and Q are situated at (3,3)m and (6,0)m respectively. The potential difference between the points P and Q will be :
Official previous-year question
Held on 27 Jan 2024 · Verified 6 Jul 2026.
Options
A
3V
B
6V
C
0V
D
3V
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Solution
The formula to calculate the potential difference between P and Q is given by
ΔV=kq(r11−r21)...(1)
Now,
r1==(3)2+(3)2m6m
And,
r2==(6)2+0m6m
As r1=r2=6m and the value of the charge remains constant, the potential difference between the points is zero.
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