Rated power & voltage gives resistance $\begin{aligned}
& \mathrm{R}=\frac{\mathrm{V}^2}{\mathrm{P}}=\frac{(200)^2}{50}=\frac{40000}{50} \
& \mathrm{R}=800 \
& \mathrm{P}=\frac{\left(\mathrm{V}_{\text {applied }}\right)^2}{\mathrm{R}}=\frac{(100)^2}{800} \
& \mathrm{P}=12.5 \text { watt }
\end{aligned}$