
Under the balanced state, there is no flow of charge through the capacitor. So, the path connecting the capacitor behaves as an open path.
The equivalent resistance of the entire circuit, under equilibrium condition, can be calculated as follows:
Req===1+4+4+41+411Ω(1+3)Ω4Ω
Hence, the current through the entire circuit is given by
I==ReqV49A
So, the current (I1) can be written as
I1==49×164A169A
The potential difference between the points A and B is,
VA−VB===I1×8169×829V
Hence, the energy stored in the capacitor is given by
U===21C(VA−VB)221×4×481μJ281μJ
∴x=81