
The linear charge density of the ring is given by
λ=2πRQ...(1)
With reference to the above diagram, for the equilibrium condition of the ring, it can be written that
2Tsin(2dθ)=4πϵ01R2q0⋅[λ(Rdθ)]
⇒T=4πϵ01(R2)×2πq0Q [As for very small angles sin(2dθ)=2dθ]
=(0.30)2×2π(9×109)(2π×30×10−12)
=9×10−29×10−3×30=3N