Net force on proton inside an electric and a magnetic field is given by
Fe+Fm=qE+q(v×B)...(1)
If both E and B are zero, then Fe and Fm both are zero. Hence, velocity may remain constant. Therefore, option (A) is correct.
If E=0,B=0, but velocity is parallel or antiparallel to the magnetic field, then also Fe and Fm both are zero. Hence, option (B) is also correct.
If E=0,B=0, but Fe+Fm=0, then also velocity may remain constant. Thus, option (D) is also correct.