Rheater =PV2=1000(100)2=10Ω For heater P=RV2⇒V=PR V=62.5×10 V=25v 
i1=1075=7.5 A,iH=1025=2.5 A.iR=i1−iH=5 V=IRR=525=5Ω
JEE Main 2024 — Physics Electromagnetism
A heater is designed to operate with a power of 1000 W in a 100 V line. It is connected in combination with a resistance of 10Ω and a resistance R, to a 100 V mains as shown in figure. For the heater to operate at 62.5 W, the value of R should be _____Ω. 
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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