ig=400+10010=20×10−3 A For ammeter Let shunt resistance =S $\begin{aligned}
& \mathrm{i}{\mathrm{g}} \mathrm{R}=\left(\mathrm{i}-\mathrm{i}{\mathrm{g}}\right) \mathrm{S} \
& 20 \times 10^{-3} \times 100=10 \mathrm{S} \
& \mathrm{S}=20 \times 10^{-2} \Omega
\end{aligned}$