
Equivalent internal resistance of two cells in parallel is req=r1+r2r1r2=3+63×6=2Ω
Equivalent emf of given cells
Eeq=(r1E1−r2E2)req=(312−66)2=6V
Given: R=4Ω
The circuit can be redrawn as shown below.

Current through resistor R is I=2+46=1A.