
The magnetic field at point O due to the two semi-infinite portions of both wires lying along line BE will be 0.
Using right-hand rule, it can be determined that the magnetic field due to both the semi-infinite portions of wires BCandET which are perpendicular to BE will be outwards from the plane.
The magnetic field due to one such portion will be:
B=4π(2a)μ0I
Since the magnetic field of both the portions is in same direction, the net magnetic field at O will be:
Bnet=2×4π(2a)μ0I=πaμ0I
.