The given circuit can be redrawn as shown below:

Since the circuit is in balanced wheatstone configuration, 2RR=6R3R.
The 9Ω resistor can be omitted. Now, the circuit has two branches having two resistors connected in series.
Therefore, the resistance of upper branch is R+3R=4R and lower branch is 2R+6R=8R.
The equivalent resistance will therefore be:
Req=4R+8R(4R)(8R)=12R32R2=38R
