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The energy density associated with electric field E and magnetic field B of an electromagnetic wave in free space is given by (ε _0- permittivity of…

JEE Main 2023 — Physics Electromagnetism

2023mcqeasy

The energy density associated with electric field E⃗\vec{E}E and magnetic field B⃗\vec{B}B of an electromagnetic wave in free space is given by (ϵ0−{\epsilon }_{0}-ϵ0​− permittivity of free space, μ0−{\mu }_{0}-μ0​− permeability of free space)

Official previous-year question

Held on 6 Apr 2023 · Verified 6 Jul 2026.

Options

  1. A

    UE=E22ϵ0,UB=B22μ0{U}_{E}=\frac{{E}^{2}}{2{\epsilon }_{0}},{U}_{B}=\frac{{B}^{2}}{2{\mu }_{0}}UE​=2ϵ0​E2​,UB​=2μ0​B2​

  2. B

    UE=ϵ0E22,UB=B22μ0{U}_{E}=\frac{{\epsilon }_{0}{E}^{2}}{2},{U}_{B}=\frac{{B}^{2}}{2{\mu }_{0}}UE​=2ϵ0​E2​,UB​=2μ0​B2​

  3. C

    UE=ϵ0E22,UB=μ0B22{U}_{E}=\frac{{\epsilon }_{0}{E}^{2}}{2},{U}_{B}=\frac{{\mu }_{0}{B}^{2}}{2}UE​=2ϵ0​E2​,UB​=2μ0​B2​

  4. D

    UE=E22ϵ0,UB=μ0B22{U}_{E}=\frac{{E}^{2}}{2{\epsilon }_{0}},{U}_{B}=\frac{{\mu }_{0}{B}^{2}}{2}UE​=2ϵ0​E2​,UB​=2μ0​B2​

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