Magnetic field at the centre of the coil is given by, B=2Rμ0i.
Now in the first case:
B=4(2Rμ0i)
and for the second case:
B′=2R′μ0i.
As the length of the wire will remain same, therefore
2πR′=4(2πR)⇒R′=4R
Hence, required ratio will be
BB′=4R′R=161
⇒B′=2T