
Current flowing through both capacitors will be zero at steady state.
The potential difference across capacitor C1 will be the sum of the potential difference across the resistor 6Ω and the galvanometer resistance. Mathematically,
VC1=i[6Ω+RG]...(1)
Similarly, the potential difference across capacitor C2 will be the sum of the potential difference across the resistor 8Ω and the galvanometer resistance. Mathematically,
VC2=i[RG+8Ω]...(2)
Divide equation (1) by equation (2) to obtain the required ratio.
VC2VC1===i[RG+8Ω]i[6Ω+RG]2Ω+8Ω6Ω+2Ω54
