In steady state, capacitor behaves as open circuit, so no current will flow.
The total resistance of the circuit is, R=(6+4)Ω=10Ω
The current flowing through the circuit is
I=10Ω3V
Potential difference on 6Ω resistor
V′=103×6=1.8V
The charge on the capacitor is,
Q=CV′=4μF×1.8V=7.2μC
