All the capacitors are in parallel combination and therefore potential drop across each capacitor would be the same.
Charge on the capacitor can be written as, Q=CV.
The charge on C1 is Q1=2×10=20μC
The charge on C2 is Q2=x×10=10xμC
The charge on C3 is Q3=3×10=30μC
By the given data.
C1+C2+C3=100μC
⇒10(2+x+3)=100
⇒x=5
