
Potential distribution at each point in the circuit is shown in above diagram.
Since, both 10Ω resistors are maintained at same potential difference, so current will be same, thus, using Ohm's law, I1=I2=1020−10=1A
Now, current I3=1010=1A
Hence, the value of ∣I2I1+I3∣=11+1=2.
