
At steady state current will not pass through capacitor, therefore effective resistance between B and C will be only 1Ω. Modified circuit will be as shown below.

⇒iAB=36=2A and iAD=126=0.5A
Applying Kirchoff's law along path BAD, we get
⇒VB+(2×2)−(10×0.5)=VD
⇒VB−VD=1V.
