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Experimentally it is found that 12.8 eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the…

JEE Main 2023 — Physics Electromagnetism

2023integereasy

Experimentally it is found that 12.8eV12.8\mathrm{eV}12.8eV energy is required to separate a hydrogen atom into a proton and an electron. So the orbital radius of the electron in a hydrogen atom is 9x×10−10m\frac{9}{x}\times {10}^{-10}mx9​×10−10m.

The value of the xxx is: _____.

(1eV=1.6×10−19J,14πϵ0=9×109Nm2C21\mathrm{eV}=1.6\times {10}^{-19}J,\frac{1}{4\pi {\epsilon }_{0}}=9\times {10}^{9}\frac{{\mathrm{Nm}}^{2}}{{C}^{2}}1eV=1.6×10−19J,4πϵ0​1​=9×109C2Nm2​ and electronic charge =1.6×10−19C=1.6\times {10}^{-19}C=1.6×10−19C)

Official previous-year question

Held on 6 Apr 2023 · Verified 6 Jul 2026.

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