Using Gauss law for a cylindrical surface around the wire: E × 2πrl = λl/ε₀. So E = λ/(2πε₀r)
Back to JEE Main 2023 Electromagnetism
JEE Main 2023 — Physics Electromagnetism
medium
mcq
2023
Official previous-year question
Verified 30 May 2026.
Question
The electric field at a distance r from an infinitely long uniformly charged wire having linear charge density λ is:
Options
- Aλ/(2πε₀r)
- Bλ/(4πε₀r)
- Cλ/(2πε₀r²)
- Dλ/(4πε₀r²)
Solution
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