An LCR series circuit of capacitance 62.5 nF and resistance of 50Ω, is connected to an A.C. source of frequency 2.0 kHz. For maximum value of…
JEE Main 2023 — Physics Electromagnetism
2023integerhard
An LCR series circuit of capacitance 62.5nF and resistance of 50Ω, is connected to an A.C. source of frequency 2.0kHz. For maximum value of amplitude of current in circuit, the value of inductance is ____mH.(Takeπ2=10)
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Held on 25 Jan 2023 · Verified 6 Jul 2026.
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Solution
Given here, f=2kHz=2000Hz,C=62.5nF=62.5×10−9FandR=50Ω
Resonance frequency (amplitude of the current will be maximum in this case) is given by f=2πLC1, here, L is the inductance.
Putting the values,
2000Hz=2πL×62.5×10−91
L=4π2×20002×62.5×10−91=0.1H=100mH
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