
The expression of motional emf is e=BLvsinθ, where, θ is angle between magnetic field and direction of motion.
Here, θ=90∘,
So, induced emf across the ends of wire is e=BLvsin90∘=BLv
=2×1×8=16V
JEE Main 2023 — Physics Electromagnetism
A wire of length 1m moving with velocity 8ms−1 at right angles to a magnetic field of 2T. The magnitude of induced emf, between the ends of wire will be ___________.
Held on 25 Jan 2023 · Verified 6 Jul 2026.
20V
8V
12V
16V
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