Given here, I=2A,V=3.4V,m=8.92×10−3kg,
d=8.92×103kgm−3andρ=1.7×10−8Ω−m
From Ohm's law, resistance is R=IV=23.4=1.7Ω
As resistance of wire is given by R=Aρl, where, A is area and l is length of wire.
⇒1.7=Aρl ⇒l=ρ1.7A
Now, volume=dm=8.92×1038.92×10−3=10−6m3
Thus,
l2=ρ1.7A×l=ρ1.7(lvolume)×l=ρ1.7(10−6)=1.7×10−81.7×10−6
Hence, l=10m