
Let the charge 40μC be placed at a distance X0 from the origin as shown in the figure.
For the electric field at x=2 to be 0,
EP=0⇒22k×10=(X0−2)2k×40
⇒21=X0−22
⇒X0−2=4
Therefore, the charge is located at X0=4+2=6cm
JEE Main 2023 — Physics Electromagnetism
A point charge of 10μC is placed at the origin. At what location on the X-axis should a point charge of 40μC be placed so that the net electric field is zero at x=2cm on the X-axis ?
Held on 25 Jan 2023 · Verified 6 Jul 2026.
x=6cm
x=4cm
x=8cm
x=–4cm
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