For balancing of force,
Magnetic force (Fm)=weight of supporting mass (mg).
∴ILB=mg
∴(RV)LB=mg(∵From Ohm’s law,I=RV)
∴V=LBmgR
=(0.1m)(103×10−4T)(1×10−3kg)(10ms−2)(10Ω)=10V
A massless square loop, of wire of resistance 10Ω, supporting a mass of 1g, hangs vertically with one of its sides in a uniform magnetic field of 103G, directed outwards in the shaded region. A dc voltage V is applied to the loop. For what value of V, the magnetic force will exactly balance the weight of the supporting mass of 1g?
(If sides of the loop =10cm,g=10ms−2)
.
Held on 30 Jan 2023 · Verified 6 Jul 2026.
101V
100V
1V
10V
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