When a charged capacitor is connected to an uncharged capacitor, then there is loss of energy in the form of heat as charges flow from higher potential to lower potential.
So, heat ΔH=21C1+C2C1C2(V1−V2)2
As the other capacitor is identical therefore charge is equally divided.
=212CC2(100−0)2
=212900×10−6×104=49 Joule
=2.25 Joule.
Hence, the value of x=225.