Capacitance of the parallel plate capacitor when air is present C=dϵ0A=5μF
After insertion of dielectric, the equivalent capacitance of the new capacitor is
Ceq=1.52d+12dϵ0A
=(3d+2d)ϵ0A=5d6ϵ0A
=56×5μF=6μF.
A capacitor has capacitance 5μF when its parallel plates are separated by air medium of thickness d. A slab of material of dielectric constant 1.5 having area equal to that of plates but thickness 2d is inserted between the plates. Capacitance of the capacitor in the presence of slab will be ______ μF.
Held on 25 Jan 2023 · Verified 6 Jul 2026.
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