When two conductors are connected by a conducting wire, their potentials become equal. Therefore, VA=VB
The potential of a spherical conductor is given by, V=RkQ
⇒RAkQA=RBkQB
⇒Q∝R
Now the electric field near the surface of the conductor will be, E=R2kQ
⇒EBEA=RB2kQBRA2kQA=RARB
⇒EBEA=510=12